Explain average velocity,instantaneous velocity,and components of velocity for motion in a plane.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The average velocity $(\vec{v})$ of an object is the ratio of the displacement and the corresponding time interval.
Suppose an object covers a displacement $\Delta \vec{r}$ in a time interval $\Delta t$.
Average velocity is given by:
$\langle\vec{v}\rangle = \frac{\Delta \vec{r}}{\Delta t} = \frac{\Delta x \hat{i} + \Delta y \hat{j}}{\Delta t} = \hat{i} \left( \frac{\Delta x}{\Delta t} \right) + \hat{j} \left( \frac{\Delta y}{\Delta t} \right)$
Or,$\langle\vec{v}\rangle = \langle v_{x} \rangle \hat{i} + \langle v_{y} \rangle \hat{j}$
The direction of the average velocity is the same as that of the displacement vector $\Delta \vec{r}$.
Instantaneous velocity is defined as the limiting value of the average velocity as the time interval approaches zero:
$\vec{v} = \lim_{\Delta t \rightarrow 0} \frac{\Delta \vec{r}}{\Delta t} = \frac{d\vec{r}}{dt}$
The direction of velocity at any point on the path is tangential to the path at that point and is in the direction of motion.
In terms of components,the instantaneous velocity is:
$\vec{v} = \hat{i} \left( \frac{dx}{dt} \right) + \hat{j} \left( \frac{dy}{dt} \right) = v_{x} \hat{i} + v_{y} \hat{j}$
where $v_{x} = \frac{dx}{dt}$ and $v_{y} = \frac{dy}{dt}$ are the components of velocity along the $x$ and $y$ axes respectively.
The magnitude of the velocity vector is given by:
$v = \sqrt{v_{x}^{2} + v_{y}^{2}}$
The units of velocity in the $MKS$ system are $m/s$ and in the $CGS$ system are $cm/s$.

Explore More

Similar Questions

Consider the motion of a particle described by $x = a \cos t$, $y = a \sin t$, and $z = t$. The trajectory traced by the particle as a function of time is

The position coordinates of a particle moving in a $3-D$ coordinate system are given by $x = a \cos \omega t$,$y = a \sin \omega t$,and $z = a \omega t$. The speed of the particle is:

At time $t = 0$,a particle starts travelling from a height of $7 \, \text{cm}$ along the $z$-axis in a plane,keeping the $z$-coordinate constant. At any instant of time,its positions along the $x$ and $y$ directions are defined as $x = 3t$ and $y = 5t^3$ respectively. What will be the acceleration of the particle at $t = 1 \, \text{s}$?

$A$ particle starts from the origin at $t=0$ with a velocity $5.0 \hat{i} \; m/s$ and moves in the $x-y$ plane under the action of a force which produces a constant acceleration of $(3.0 \hat{i} + 2.0 \hat{j}) \; m/s^2$.
$(a)$ What is the $y$-coordinate of the particle at the instant its $x$-coordinate is $84 \; m$?
$(b)$ What is the speed of the particle at this time?

$A$ particle starts from the origin at $t=0$ with a velocity of $10 \hat{j} \text{ ms}^{-1}$ and moves in the $x-y$ plane with a constant acceleration of $(8 \hat{i} + 2 \hat{j}) \text{ ms}^{-2}$. At an instant when the $x$-coordinate of the particle is $16 \text{ m}$, the $y$-coordinate of the particle is: (in $\text{ m}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo